64x^2-16x-63=0

Solution for 64x^2-16x-63=0 equation:

64x^2-16x-63=0

a = 64; b = -16; c = -63;
Δ = b2-4ac
Δ = -162-4·64·(-63)
Δ = 16384
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16384}=128$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-128}{2*64}=\frac{-112}{128}
=-7/8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+128}{2*64}=\frac{144}{128}
=1+1/8
$